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30=x^2+3x
We move all terms to the left:
30-(x^2+3x)=0
We get rid of parentheses
-x^2-3x+30=0
We add all the numbers together, and all the variables
-1x^2-3x+30=0
a = -1; b = -3; c = +30;
Δ = b2-4ac
Δ = -32-4·(-1)·30
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{129}}{2*-1}=\frac{3-\sqrt{129}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{129}}{2*-1}=\frac{3+\sqrt{129}}{-2} $
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